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2x+3(x-2)=6-4(2x+3)
We move all terms to the left:
2x+3(x-2)-(6-4(2x+3))=0
We multiply parentheses
2x+3x-(6-4(2x+3))-6=0
We calculate terms in parentheses: -(6-4(2x+3)), so:We add all the numbers together, and all the variables
6-4(2x+3)
determiningTheFunctionDomain -4(2x+3)+6
We multiply parentheses
-8x-12+6
We add all the numbers together, and all the variables
-8x-6
Back to the equation:
-(-8x-6)
5x-(-8x-6)-6=0
We get rid of parentheses
5x+8x+6-6=0
We add all the numbers together, and all the variables
13x=0
x=0/13
x=0
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