2(p-3)+7(p-4)=29

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Solution for 2(p-3)+7(p-4)=29 equation: 



2(p-3)+7(p-4)=29

We move all terms to the left:

2(p-3)+7(p-4)-(29)=0

We multiply parentheses

2p+7p-6-28-29=0

We add all the numbers together, and all the variables

9p-63=0

We move all terms containing p to the left, all other terms to the right

9p=63

p=63/9

p=7

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