2x+2x+(4x+8)2=88

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Solution for 2x+2x+(4x+8)2=88 equation: 



2x+2x+(4x+8)2=88

We move all terms to the left:

2x+2x+(4x+8)2-(88)=0

We add all the numbers together, and all the variables

4x+(4x+8)2-88=0

We multiply parentheses

4x+8x+16-88=0

We add all the numbers together, and all the variables

12x-72=0

We move all terms containing x to the left, all other terms to the right

12x=72

x=72/12

x=6

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