2x-4(x+5)=7+4x-21

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Solution for 2x-4(x+5)=7+4x-21 equation: 



2x-4(x+5)=7+4x-21

We move all terms to the left:

2x-4(x+5)-(7+4x-21)=0

We add all the numbers together, and all the variables

2x-4(x+5)-(4x-14)=0

We multiply parentheses

2x-4x-(4x-14)-20=0

We get rid of parentheses

2x-4x-4x+14-20=0

We add all the numbers together, and all the variables

-6x-6=0

We move all terms containing x to the left, all other terms to the right

-6x=6

x=6/-6

x=-1

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