2x+20+x=40x(2)

Solution for 2x+20+x=40x(2) equation:

2x+20+x=40x(2)

We move all terms to the left:

2x+20+x-(40x(2))=0

determiningTheFunctionDomain
2x+x-40x2+20=0

We add all the numbers together, and all the variables

-40x^2+3x+20=0

a = -40; b = 3; c = +20;
Δ = b2-4ac
Δ = 32-4·(-40)·20
Δ = 3209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{3209}}{2*-40}=\frac{-3-\sqrt{3209}}{-80}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{3209}}{2*-40}=\frac{-3+\sqrt{3209}}{-80}
$