7(3x-8)=3(-6x+4)+127

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Solution for 7(3x-8)=3(-6x+4)+127 equation: 



7(3x-8)=3(-6x+4)+127

We move all terms to the left:

7(3x-8)-(3(-6x+4)+127)=0

We multiply parentheses

21x-(3(-6x+4)+127)-56=0



We calculate terms in parentheses: -(3(-6x+4)+127), so:

3(-6x+4)+127

We multiply parentheses

-18x+12+127

We add all the numbers together, and all the variables

-18x+139

Back to the equation:

-(-18x+139)



We get rid of parentheses

21x+18x-139-56=0

We add all the numbers together, and all the variables

39x-195=0

We move all terms containing x to the left, all other terms to the right

39x=195

x=195/39

x=5

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