2x+2-x=3(x-4)+2

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Solution for 2x+2-x=3(x-4)+2 equation: 



2x+2-x=3(x-4)+2

We move all terms to the left:

2x+2-x-(3(x-4)+2)=0

We add all the numbers together, and all the variables

x-(3(x-4)+2)+2=0



We calculate terms in parentheses: -(3(x-4)+2), so:

3(x-4)+2

We multiply parentheses

3x-12+2

We add all the numbers together, and all the variables

3x-10

Back to the equation:

-(3x-10)



We get rid of parentheses

x-3x+10+2=0

We add all the numbers together, and all the variables

-2x+12=0

We move all terms containing x to the left, all other terms to the right

-2x=-12

x=-12/-2

x=+6

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