6(a-2)=4(a-3)+2a

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Solution for 6(a-2)=4(a-3)+2a equation: 



6(a-2)=4(a-3)+2a

We move all terms to the left:

6(a-2)-(4(a-3)+2a)=0

We multiply parentheses

6a-(4(a-3)+2a)-12=0



We calculate terms in parentheses: -(4(a-3)+2a), so:

4(a-3)+2a

We add all the numbers together, and all the variables

2a+4(a-3)

We multiply parentheses

2a+4a-12

We add all the numbers together, and all the variables

6a-12

Back to the equation:

-(6a-12)



We get rid of parentheses

6a-6a+12-12=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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