2x+2(x-3)=58

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Solution for 2x+2(x-3)=58 equation: 



2x+2(x-3)=58

We move all terms to the left:

2x+2(x-3)-(58)=0

We multiply parentheses

2x+2x-6-58=0

We add all the numbers together, and all the variables

4x-64=0

We move all terms containing x to the left, all other terms to the right

4x=64

x=64/4

x=16

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