(3/2)(4p-6)=(2/9)(27p-45)

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Solution for (3/2)(4p-6)=(2/9)(27p-45) equation: 



(3/2)(4p-6)=(2/9)(27p-45)

We move all terms to the left:

(3/2)(4p-6)-((2/9)(27p-45))=0



Domain of the equation: 2)(4p-6)!=0

p∈R





Domain of the equation: 9)(27p-45))!=0

p∈R



We add all the numbers together, and all the variables

(+3/2)(4p-6)-((+2/9)(27p-45))=0

We multiply parentheses ..

(+12p^2+3/2*-6)-((+2/9)(27p-45))=0

We calculate fractions


((+12p^2+3*9)(27p-45)))/(-6)*9)(27p-45))+2*)+()/(-6)*9)(27p-45))+2*)=0

We calculate fractions


(((+12p^2+3*9)(27p-45)))*(-6)*9)(27p-45))+2*))/((*(-6)*9)27p)+(-6)*9)(27p-45))+2*)+()*()/((*(-6)*9)27p)=0

We can not solve this equation

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