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2x(x+5)=82
We move all terms to the left:
2x(x+5)-(82)=0
We multiply parentheses
2x^2+10x-82=0
a = 2; b = 10; c = -82;
Δ = b2-4ac
Δ = 102-4·2·(-82)
Δ = 756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{756}=\sqrt{36*21}=\sqrt{36}*\sqrt{21}=6\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-6\sqrt{21}}{2*2}=\frac{-10-6\sqrt{21}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+6\sqrt{21}}{2*2}=\frac{-10+6\sqrt{21}}{4} $
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