2x+2(6x-10)=106

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Solution for 2x+2(6x-10)=106 equation: 



2x+2(6x-10)=106

We move all terms to the left:

2x+2(6x-10)-(106)=0

We multiply parentheses

2x+12x-20-106=0

We add all the numbers together, and all the variables

14x-126=0

We move all terms containing x to the left, all other terms to the right

14x=126

x=126/14

x=9

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