4m+(6m+12)=(72+2m)

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Solution for 4m+(6m+12)=(72+2m) equation: 



4m+(6m+12)=(72+2m)

We move all terms to the left:

4m+(6m+12)-((72+2m))=0

We add all the numbers together, and all the variables

4m+(6m+12)-((2m+72))=0

We get rid of parentheses

4m+6m-((2m+72))+12=0



We calculate terms in parentheses: -((2m+72)), so:

(2m+72)

We get rid of parentheses

2m+72

Back to the equation:

-(2m+72)



We add all the numbers together, and all the variables

10m-(2m+72)+12=0

We get rid of parentheses

10m-2m-72+12=0

We add all the numbers together, and all the variables

8m-60=0

We move all terms containing m to the left, all other terms to the right

8m=60

m=60/8

m=7+1/2

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