2x+10=2(11/2x+5)

Solution for 2x+10=2(11/2x+5) equation:

2x+10=2(11/2x+5)

We move all terms to the left:

2x+10-(2(11/2x+5))=0


Domain of the equation: 2x+5))!=0

x∈R


We multiply all the terms by the denominator


2x*2x+10*2x+5))-(2(11+5))=0

We add all the numbers together, and all the variables

2x*2x+10*2x+5))-(216)=0

We add all the numbers together, and all the variables

2x*2x+10*2x=0

Wy multiply elements

4x^2+20x=0

a = 4; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·4·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*4}=\frac{-40}{8}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*4}=\frac{0}{8}
=0
$