2(x+2)-3(x-2)=6(x-6)

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Solution for 2(x+2)-3(x-2)=6(x-6) equation: 



2(x+2)-3(x-2)=6(x-6)

We move all terms to the left:

2(x+2)-3(x-2)-(6(x-6))=0

We multiply parentheses

2x-3x-(6(x-6))+4+6=0



We calculate terms in parentheses: -(6(x-6)), so:

6(x-6)

We multiply parentheses

6x-36

Back to the equation:

-(6x-36)



We add all the numbers together, and all the variables

-1x-(6x-36)+10=0

We get rid of parentheses

-1x-6x+36+10=0

We add all the numbers together, and all the variables

-7x+46=0

We move all terms containing x to the left, all other terms to the right

-7x=-46

x=-46/-7

x=6+4/7

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