2x+1/x-5=2

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Solution for 2x+1/x-5=2 equation:



2x+1/x-5=2
We move all terms to the left:
2x+1/x-5-(2)=0
Domain of the equation: x!=0
x∈R
We add all the numbers together, and all the variables
2x+1/x-7=0
We multiply all the terms by the denominator
2x*x-7*x+1=0
We add all the numbers together, and all the variables
-7x+2x*x+1=0
Wy multiply elements
2x^2-7x+1=0
a = 2; b = -7; c = +1;
Δ = b2-4ac
Δ = -72-4·2·1
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{41}}{2*2}=\frac{7-\sqrt{41}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{41}}{2*2}=\frac{7+\sqrt{41}}{4} $

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