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5(x-3)=2(3+x)
We move all terms to the left:
5(x-3)-(2(3+x))=0
We add all the numbers together, and all the variables
5(x-3)-(2(x+3))=0
We multiply parentheses
5x-(2(x+3))-15=0
We calculate terms in parentheses: -(2(x+3)), so:We get rid of parentheses
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
5x-2x-6-15=0
We add all the numbers together, and all the variables
3x-21=0
We move all terms containing x to the left, all other terms to the right
3x=21
x=21/3
x=7
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