2x+(X+1)+(X+2)=108

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Solution for 2x+(X+1)+(X+2)=108 equation: 



2x+(x+1)+(x+2)=108

We move all terms to the left:

2x+(x+1)+(x+2)-(108)=0

We get rid of parentheses

2x+x+x+1+2-108=0

We add all the numbers together, and all the variables

4x-105=0

We move all terms containing x to the left, all other terms to the right

4x=105

x=105/4

x=26+1/4

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