2x+(36/5)=5

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Solution for 2x+(36/5)=5 equation: 



2x+(36/5)=5

We move all terms to the left:

2x+(36/5)-(5)=0

determiningTheFunctionDomain
2x-5+(36/5)=0

We add all the numbers together, and all the variables

2x-5+(+36/5)=0

We get rid of parentheses

2x-5+36/5=0

We multiply all the terms by the denominator


2x*5+36-5*5=0

We add all the numbers together, and all the variables

2x*5+11=0

Wy multiply elements

10x+11=0

We move all terms containing x to the left, all other terms to the right

10x=-11

x=-11/10

x=-1+1/10

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