x+2(2x+3)-1=(1/2)(4x+28)

Solution for x+2(2x+3)-1=(1/2)(4x+28) equation:

x+2(2x+3)-1=(1/2)(4x+28)

We move all terms to the left:

x+2(2x+3)-1-((1/2)(4x+28))=0


Domain of the equation: 2)(4x+28))!=0

x∈R


We add all the numbers together, and all the variables

x+2(2x+3)-((+1/2)(4x+28))-1=0

We multiply parentheses

x+4x-((+1/2)(4x+28))+6-1=0

We multiply parentheses ..

-((+4x^2+1/2*28))+x+4x+6-1=0

We multiply all the terms by the denominator


-((+4x^2+1+x*2*28))+4x*2*28))+6*2*28))-1*2*28))=0


We calculate terms in parentheses: -((+4x^2+1+x*2*28)), so:

(+4x^2+1+x*2*28)

We get rid of parentheses

4x^2+x*2*28+1

Wy multiply elements

4x^2+56x*2+1

Wy multiply elements

4x^2+112x+1

Back to the equation:

-(4x^2+112x+1)


Wy multiply elements

702464x^4*2-(4x^2+112x+1)=0

We get rid of parentheses

702464x^4*2-4x^2-112x-1=0

We do not support expression: x^4