2x+(15-3x)+6=10+(-5x+31)-x

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Solution for 2x+(15-3x)+6=10+(-5x+31)-x equation: 



2x+(15-3x)+6=10+(-5x+31)-x

We move all terms to the left:

2x+(15-3x)+6-(10+(-5x+31)-x)=0

We add all the numbers together, and all the variables

2x+(-3x+15)-(10+(-5x+31)-x)+6=0

We get rid of parentheses

2x-3x-(10+(-5x+31)-x)+15+6=0



We calculate terms in parentheses: -(10+(-5x+31)-x), so:

10+(-5x+31)-x

determiningTheFunctionDomain
(-5x+31)-x+10

We add all the numbers together, and all the variables

-1x+(-5x+31)+10

We get rid of parentheses

-1x-5x+31+10

We add all the numbers together, and all the variables

-6x+41

Back to the equation:

-(-6x+41)



We add all the numbers together, and all the variables

-1x-(-6x+41)+21=0

We get rid of parentheses

-1x+6x-41+21=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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