28+2y-11=11y-11-5y

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Solution for 28+2y-11=11y-11-5y equation: 



28+2y-11=11y-11-5y

We move all terms to the left:

28+2y-11-(11y-11-5y)=0

We add all the numbers together, and all the variables

2y-(6y-11)+28-11=0

We add all the numbers together, and all the variables

2y-(6y-11)+17=0

We get rid of parentheses

2y-6y+11+17=0

We add all the numbers together, and all the variables

-4y+28=0

We move all terms containing y to the left, all other terms to the right

-4y=-28

y=-28/-4

y=+7

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