2x+(1/2x)=180

Solution for 2x+(1/2x)=180 equation:

2x+(1/2x)=180

We move all terms to the left:

2x+(1/2x)-(180)=0


Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x+(+1/2x)-180=0

We get rid of parentheses

2x+1/2x-180=0

We multiply all the terms by the denominator


2x*2x-180*2x+1=0

Wy multiply elements

4x^2-360x+1=0

a = 4; b = -360; c = +1;
Δ = b2-4ac
Δ = -3602-4·4·1
Δ = 129584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{129584}=\sqrt{16*8099}=\sqrt{16}*\sqrt{8099}=4\sqrt{8099}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-360)-4\sqrt{8099}}{2*4}=\frac{360-4\sqrt{8099}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-360)+4\sqrt{8099}}{2*4}=\frac{360+4\sqrt{8099}}{8}
$