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(3x+4)-(2x+1)=5(x-1)+8
We move all terms to the left:
(3x+4)-(2x+1)-(5(x-1)+8)=0
We get rid of parentheses
3x-2x-(5(x-1)+8)+4-1=0
We calculate terms in parentheses: -(5(x-1)+8), so:We add all the numbers together, and all the variables
5(x-1)+8
We multiply parentheses
5x-5+8
We add all the numbers together, and all the variables
5x+3
Back to the equation:
-(5x+3)
x-(5x+3)+3=0
We get rid of parentheses
x-5x-3+3=0
We add all the numbers together, and all the variables
-4x=0
x=0/-4
x=0
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