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2x*2x+220x=3000
We move all terms to the left:
2x*2x+220x-(3000)=0
We add all the numbers together, and all the variables
220x+2x*2x-3000=0
Wy multiply elements
4x^2+220x-3000=0
a = 4; b = 220; c = -3000;
Δ = b2-4ac
Δ = 2202-4·4·(-3000)
Δ = 96400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{96400}=\sqrt{400*241}=\sqrt{400}*\sqrt{241}=20\sqrt{241}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(220)-20\sqrt{241}}{2*4}=\frac{-220-20\sqrt{241}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(220)+20\sqrt{241}}{2*4}=\frac{-220+20\sqrt{241}}{8} $
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