340=a(a+3)

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Solution for 340=a(a+3) equation:



340=a(a+3)
We move all terms to the left:
340-(a(a+3))=0
We calculate terms in parentheses: -(a(a+3)), so:
a(a+3)
We multiply parentheses
a^2+3a
Back to the equation:
-(a^2+3a)
We get rid of parentheses
-a^2-3a+340=0
We add all the numbers together, and all the variables
-1a^2-3a+340=0
a = -1; b = -3; c = +340;
Δ = b2-4ac
Δ = -32-4·(-1)·340
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-37}{2*-1}=\frac{-34}{-2} =+17 $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+37}{2*-1}=\frac{40}{-2} =-20 $

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