2x(x-7)=x(x-3)

Solution for 2x(x-7)=x(x-3) equation:

2x(x-7)=x(x-3)

We move all terms to the left:

2x(x-7)-(x(x-3))=0

We multiply parentheses

2x^2-14x-(x(x-3))=0


We calculate terms in parentheses: -(x(x-3)), so:

x(x-3)

We multiply parentheses

x^2-3x

Back to the equation:

-(x^2-3x)


We get rid of parentheses

2x^2-x^2-14x+3x=0

We add all the numbers together, and all the variables

x^2-11x=0

a = 1; b = -11; c = 0;
Δ = b2-4ac
Δ = -112-4·1·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-11}{2*1}=\frac{0}{2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+11}{2*1}=\frac{22}{2}
=11
$