7(5x-3)=65+4(2-3x)

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Solution for 7(5x-3)=65+4(2-3x) equation: 



7(5x-3)=65+4(2-3x)

We move all terms to the left:

7(5x-3)-(65+4(2-3x))=0

We add all the numbers together, and all the variables

7(5x-3)-(65+4(-3x+2))=0

We multiply parentheses

35x-(65+4(-3x+2))-21=0



We calculate terms in parentheses: -(65+4(-3x+2)), so:

65+4(-3x+2)

determiningTheFunctionDomain
4(-3x+2)+65

We multiply parentheses

-12x+8+65

We add all the numbers together, and all the variables

-12x+73

Back to the equation:

-(-12x+73)



We get rid of parentheses

35x+12x-73-21=0

We add all the numbers together, and all the variables

47x-94=0

We move all terms containing x to the left, all other terms to the right

47x=94

x=94/47

x=2

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