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2x(x-2)-51=0
We multiply parentheses
2x^2-4x-51=0
a = 2; b = -4; c = -51;
Δ = b2-4ac
Δ = -42-4·2·(-51)
Δ = 424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{424}=\sqrt{4*106}=\sqrt{4}*\sqrt{106}=2\sqrt{106}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{106}}{2*2}=\frac{4-2\sqrt{106}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{106}}{2*2}=\frac{4+2\sqrt{106}}{4} $
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