(x/3)=7x/(12x-15)

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Solution for (x/3)=7x/(12x-15) equation: 



(x/3)=7x/(12x-15)

We move all terms to the left:

(x/3)-(7x/(12x-15))=0



Domain of the equation: (12x-15))!=0

x∈R



We add all the numbers together, and all the variables

(+x/3)-(7x/(12x-15))=0

We get rid of parentheses

x/3-(7x/(12x-15))=0

We calculate fractions


(-3x^2)/36x+(-(7x*3)/36x=0

We add all the numbers together, and all the variables

(-3x^2)/36x+(-(+7x*3)/36x=0

We multiply all the terms by the denominator


(-3x^2)+(-(+7x*3)=0



We calculate terms in parentheses: +(-(+7x*3), so:

-(+7x*3



We get rid of parentheses

-3x^2+(-(+7x*3)=0



We calculate terms in parentheses: +(-(+7x*3), so:

-(+7x*3





We calculate terms in parentheses: +(-(+7x*3), so:

-(+7x*3





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-(+7x*3





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-(+7x*3





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-(+7x*3





We calculate terms in parentheses: +(-(+7x*3), so:

-(+7x*3





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-(+7x*3





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-(+7x*3





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-(+7x*3





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-(+7x*3





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-(+7x*3





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-(+7x*3





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-(+7x*3





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-(+7x*3





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-(+7x*3





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