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2x(x-1)=96
We move all terms to the left:
2x(x-1)-(96)=0
We multiply parentheses
2x^2-2x-96=0
a = 2; b = -2; c = -96;
Δ = b2-4ac
Δ = -22-4·2·(-96)
Δ = 772
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{772}=\sqrt{4*193}=\sqrt{4}*\sqrt{193}=2\sqrt{193}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{193}}{2*2}=\frac{2-2\sqrt{193}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{193}}{2*2}=\frac{2+2\sqrt{193}}{4} $
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