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(2x+21)(4x+25)=714
We move all terms to the left:
(2x+21)(4x+25)-(714)=0
We multiply parentheses ..
(+8x^2+50x+84x+525)-714=0
We get rid of parentheses
8x^2+50x+84x+525-714=0
We add all the numbers together, and all the variables
8x^2+134x-189=0
a = 8; b = 134; c = -189;
Δ = b2-4ac
Δ = 1342-4·8·(-189)
Δ = 24004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24004}=\sqrt{4*6001}=\sqrt{4}*\sqrt{6001}=2\sqrt{6001}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(134)-2\sqrt{6001}}{2*8}=\frac{-134-2\sqrt{6001}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(134)+2\sqrt{6001}}{2*8}=\frac{-134+2\sqrt{6001}}{16} $
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