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2x(x+4)=6x-4
We move all terms to the left:
2x(x+4)-(6x-4)=0
We multiply parentheses
2x^2+8x-(6x-4)=0
We get rid of parentheses
2x^2+8x-6x+4=0
We add all the numbers together, and all the variables
2x^2+2x+4=0
a = 2; b = 2; c = +4;
Δ = b2-4ac
Δ = 22-4·2·4
Δ = -28
Delta is less than zero, so there is no solution for the equation
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