(x/5)=5+(x-49)/2

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Solution for (x/5)=5+(x-49)/2 equation: 



(x/5)=5+(x-49)/2

We move all terms to the left:

(x/5)-(5+(x-49)/2)=0

We add all the numbers together, and all the variables

(+x/5)-(5+(x-49)/2)=0

We get rid of parentheses

x/5-(5+(x-49)/2)=0

We calculate fractions


2x^2/()+(-(5+(x-49)*5)/()=0



We calculate terms in parentheses: +(-(5+(x-49)*5)/(), so:

-(5+(x-49)*5)/(

We multiply all the terms by the denominator


-(5+(x-49)*5)



We calculate terms in parentheses: -(5+(x-49)*5), so:

5+(x-49)*5

determiningTheFunctionDomain
(x-49)*5+5

We multiply parentheses

5x-245+5

We add all the numbers together, and all the variables

5x-240

Back to the equation:

-(5x-240)



We get rid of parentheses

-5x+240

Back to the equation:

+(-5x+240)



We get rid of parentheses

2x^2/()-5x+240=0

We multiply all the terms by the denominator


2x^2-5x*()+240*()=0

We add all the numbers together, and all the variables

2x^2-5x*()=0

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