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(x/5)=5+((x-4)/2)
We move all terms to the left:
(x/5)-(5+((x-4)/2))=0
We add all the numbers together, and all the variables
(+x/5)-(5+((x-4)/2))=0
We get rid of parentheses
x/5-(5+((x-4)/2))=0
We calculate fractions
2x^2/()+(-(5+((x-4)*5)/()=0
We calculate terms in parentheses: +(-(5+((x-4)*5)/(), so:
-(5+((x-4)*5)/(
We multiply all the terms by the denominator
-(5+((x-4)*5)
We calculate terms in parentheses: -(5+((x-4)*5), so:
5+((x-4)*5
determiningTheFunctionDomain ((x-4)*5+5
Back to the equation:
-(((x-4)*5+5)
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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((x-4)*5+5
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We calculate terms in parenthe
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