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2x(x+3)=5x-12
We move all terms to the left:
2x(x+3)-(5x-12)=0
We multiply parentheses
2x^2+6x-(5x-12)=0
We get rid of parentheses
2x^2+6x-5x+12=0
We add all the numbers together, and all the variables
2x^2+x+12=0
a = 2; b = 1; c = +12;
Δ = b2-4ac
Δ = 12-4·2·12
Δ = -95
Delta is less than zero, so there is no solution for the equation
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