10-2(3-5m)=6(m-2)

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Solution for 10-2(3-5m)=6(m-2) equation: 



10-2(3-5m)=6(m-2)

We move all terms to the left:

10-2(3-5m)-(6(m-2))=0

We add all the numbers together, and all the variables

-2(-5m+3)-(6(m-2))+10=0

We multiply parentheses

10m-(6(m-2))-6+10=0



We calculate terms in parentheses: -(6(m-2)), so:

6(m-2)

We multiply parentheses

6m-12

Back to the equation:

-(6m-12)



We add all the numbers together, and all the variables

10m-(6m-12)+4=0

We get rid of parentheses

10m-6m+12+4=0

We add all the numbers together, and all the variables

4m+16=0

We move all terms containing m to the left, all other terms to the right

4m=-16

m=-16/4

m=-4

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