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2x(x+3)=-8
We move all terms to the left:
2x(x+3)-(-8)=0
We add all the numbers together, and all the variables
2x(x+3)+8=0
We multiply parentheses
2x^2+6x+8=0
a = 2; b = 6; c = +8;
Δ = b2-4ac
Δ = 62-4·2·8
Δ = -28
Delta is less than zero, so there is no solution for the equation
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