21y-6=3(7y-2)

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Solution for 21y-6=3(7y-2) equation: 



21y-6=3(7y-2)

We move all terms to the left:

21y-6-(3(7y-2))=0



We calculate terms in parentheses: -(3(7y-2)), so:

3(7y-2)

We multiply parentheses

21y-6

Back to the equation:

-(21y-6)



We get rid of parentheses

21y-21y+6-6=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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