r+(2r+4)=(r+2r)+4=3r+4

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Solution for r+(2r+4)=(r+2r)+4=3r+4 equation: 



r+(2r+4)=(r+2r)+4=3r+4

We move all terms to the left:

r+(2r+4)-((r+2r)+4)=0

We add all the numbers together, and all the variables

r+(2r+4)-((+3r)+4)=0

We get rid of parentheses

r+2r-((+3r)+4)+4=0



We calculate terms in parentheses: -((+3r)+4), so:

(+3r)+4

We get rid of parentheses

3r+4

Back to the equation:

-(3r+4)



We add all the numbers together, and all the variables

3r-(3r+4)+4=0

We get rid of parentheses

3r-3r-4+4=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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