2x(x+2)=88

Solution for 2x(x+2)=88 equation:

2x(x+2)=88

We move all terms to the left:

2x(x+2)-(88)=0

We multiply parentheses

2x^2+4x-88=0

a = 2; b = 4; c = -88;
Δ = b2-4ac
Δ = 42-4·2·(-88)
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-12\sqrt{5}}{2*2}=\frac{-4-12\sqrt{5}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+12\sqrt{5}}{2*2}=\frac{-4+12\sqrt{5}}{4}
$