2x(x+1)=4x-8

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Solution for 2x(x+1)=4x-8 equation: 



2x(x+1)=4x-8

We move all terms to the left:

2x(x+1)-(4x-8)=0

We multiply parentheses

2x^2+2x-(4x-8)=0

We get rid of parentheses

2x^2+2x-4x+8=0

We add all the numbers together, and all the variables

2x^2-2x+8=0

a = 2; b = -2; c = +8;
Δ = b2-4ac
Δ = -22-4·2·8
Δ = -60
Delta is less than zero, so there is no solution for the equation

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