2x(x+1)+4x+1(x+1)=4x+2x(3x+2)

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Solution for 2x(x+1)+4x+1(x+1)=4x+2x(3x+2) equation: 



2x(x+1)+4x+1(x+1)=4x+2x(3x+2)

We move all terms to the left:

2x(x+1)+4x+1(x+1)-(4x+2x(3x+2))=0

We add all the numbers together, and all the variables

4x+2x(x+1)+1(x+1)-(4x+2x(3x+2))=0

We multiply parentheses

2x^2+4x+2x+1(x+1)-(4x+2x(3x+2))=0



We calculate terms in parentheses: -(4x+2x(3x+2)), so:

4x+2x(3x+2)

We multiply parentheses

6x^2+4x+4x

We add all the numbers together, and all the variables

6x^2+8x

Back to the equation:

-(6x^2+8x)



We add all the numbers together, and all the variables

2x^2+6x+1(x+1)-(6x^2+8x)=0

We get rid of parentheses

2x^2-6x^2+6x+1(x+1)-8x=0

We add all the numbers together, and all the variables

-4x^2-2x+1(x+1)=0

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