2x/12=(6+x)/18

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Solution for 2x/12=(6+x)/18 equation: 



2x/12=(6+x)/18

We move all terms to the left:

2x/12-((6+x)/18)=0

We add all the numbers together, and all the variables

2x/12-((x+6)/18)=0

We calculate fractions


36x^2/()+(-((x+6)*12)/()=0



We calculate terms in parentheses: +(-((x+6)*12)/(), so:

-((x+6)*12)/(

We multiply all the terms by the denominator


-((x+6)*12)



We calculate terms in parentheses: -((x+6)*12), so:

(x+6)*12

We multiply parentheses

12x+72

Back to the equation:

-(12x+72)



We get rid of parentheses

-12x-72

Back to the equation:

+(-12x-72)



We get rid of parentheses

36x^2/()-12x-72=0

We multiply all the terms by the denominator


36x^2-12x*()-72*()=0

We add all the numbers together, and all the variables

36x^2-12x*()=0

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