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2x(8x+9)=3+16x+15
We move all terms to the left:
2x(8x+9)-(3+16x+15)=0
We add all the numbers together, and all the variables
2x(8x+9)-(16x+18)=0
We multiply parentheses
16x^2+18x-(16x+18)=0
We get rid of parentheses
16x^2+18x-16x-18=0
We add all the numbers together, and all the variables
16x^2+2x-18=0
a = 16; b = 2; c = -18;
Δ = b2-4ac
Δ = 22-4·16·(-18)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-34}{2*16}=\frac{-36}{32} =-1+1/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+34}{2*16}=\frac{32}{32} =1 $
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