2/7(-2x-4)=5

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Solution for 2/7(-2x-4)=5 equation: 



2/7(-2x-4)=5

We move all terms to the left:

2/7(-2x-4)-(5)=0



Domain of the equation: 7(-2x-4)!=0

x∈R



We multiply all the terms by the denominator


-5*7(-2x-4)+2=0

Wy multiply elements

-35x(-+2=0

We use the square of the difference formula

-35x(-2=0

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