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4(3x-3)=-6(2-2x)
We move all terms to the left:
4(3x-3)-(-6(2-2x))=0
We add all the numbers together, and all the variables
4(3x-3)-(-6(-2x+2))=0
We multiply parentheses
12x-(-6(-2x+2))-12=0
We calculate terms in parentheses: -(-6(-2x+2)), so:We get rid of parentheses
-6(-2x+2)
We multiply parentheses
12x-12
Back to the equation:
-(12x-12)
12x-12x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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