2x(6x-1)+12=8x-x(3-12x)

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Solution for 2x(6x-1)+12=8x-x(3-12x) equation: 



2x(6x-1)+12=8x-x(3-12x)

We move all terms to the left:

2x(6x-1)+12-(8x-x(3-12x))=0

We add all the numbers together, and all the variables

2x(6x-1)-(8x-x(-12x+3))+12=0

We multiply parentheses

12x^2-2x-(8x-x(-12x+3))+12=0



We calculate terms in parentheses: -(8x-x(-12x+3)), so:

8x-x(-12x+3)

We multiply parentheses

12x^2+8x-3x

We add all the numbers together, and all the variables

12x^2+5x

Back to the equation:

-(12x^2+5x)



We get rid of parentheses

12x^2-12x^2-2x-5x+12=0

We add all the numbers together, and all the variables

-7x+12=0

We move all terms containing x to the left, all other terms to the right

-7x=-12

x=-12/-7

x=1+5/7

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