x2+32x+256=539

Solution for x2+32x+256=539 equation:

x2+32x+256=539

We move all terms to the left:

x2+32x+256-(539)=0

We add all the numbers together, and all the variables

x^2+32x-283=0

a = 1; b = 32; c = -283;
Δ = b2-4ac
Δ = 322-4·1·(-283)
Δ = 2156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2156}=\sqrt{196*11}=\sqrt{196}*\sqrt{11}=14\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-14\sqrt{11}}{2*1}=\frac{-32-14\sqrt{11}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+14\sqrt{11}}{2*1}=\frac{-32+14\sqrt{11}}{2}
$