2x(6-5x)=-7

Solution for 2x(6-5x)=-7 equation:

2x(6-5x)=-7

We move all terms to the left:

2x(6-5x)-(-7)=0

We add all the numbers together, and all the variables

2x(-5x+6)-(-7)=0

We add all the numbers together, and all the variables

2x(-5x+6)+7=0

We multiply parentheses

-10x^2+12x+7=0

a = -10; b = 12; c = +7;
Δ = b2-4ac
Δ = 122-4·(-10)·7
Δ = 424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{424}=\sqrt{4*106}=\sqrt{4}*\sqrt{106}=2\sqrt{106}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{106}}{2*-10}=\frac{-12-2\sqrt{106}}{-20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{106}}{2*-10}=\frac{-12+2\sqrt{106}}{-20}
$